Aboy pulls with a 20 n force, at a 20 degree incline. what part of the force moves the wagon?

horizontal direction force move wagon at  18.79 N

Explanation:

given data

force F = 20 N

angle = 20 degree

to find out

What part of the force moves the wagon

solution

we know here as per attach figure

boy pull a wagon at force 20 N at angle 20 degree

so there are 2 component

x in horizontal direction i.e  F cos20

and y in vertical direction i.e F sin20

so we can say

horizontal direction force is move the wagon that is

horizontal direction force = F cos 20

horizontal direction force = 20× cos20

horizontal direction force = 18.79 N

so horizontal direction force move wagon at  18.79 N