If the stopping potential of a metal when illuminated with a radiation of wavelength 480 nm is 1.2 v, find (a) the work function of the metal, (b) the cutoff wavelength of the metal, and (c) the maximum energy of the ejected electrons

Part a)

Part b)

Part c)

Explanation:

As we know by Einstein's equation of energy that

incident energy of photons = work function of metal + kinetic energy of electrons

here we know that incident energy of photons is given as

now we have

kinetic energy of ejected electrons = qV

so we have

Part a)

now we have

Part b)

in order to find cut off wavelength we know that

Part c)

Maximum energy of ejected electrons is the kinetic energy that we are getting

the kinetic energy of electrons will be obtained from stopping potential

so it is given as

you can cut your hand off if your not