An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. if the temperature at the bottom is 5.9°c and at the top 16.0°c, what is the volume of the bubble just before it reaches the surface?

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 ×  Pa

so from gas law

here p is pressure and v is volume and t is temperature

so put here value and find v1

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

it breaks and dirupture other materials and other sencews from the bottom

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!