Acheetah running at 17.5 m/s looses its prey and begins to slow down at a constant acceleraton, fianlly stopping 30.5 m later. how long does it take the cheetah to come to rest and what is the cheetah's acceleration while doing so? i know the answer which is ∆t= 3.49 s but want to see the work how it gets 3.49 s.

Explanation:

As we know that initial speed of the cheetah is given as

finally it comes to rest so final speed is given as

now we know that distance covered by cheetah while it stop is given as

now by equation of kinematics we know that

here we have

Now in order to find the acceleration we know that

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