An electric field of 790,000 n/c points due west at a certain spot. what is the magnitude of the force that acts on a charge of -3.00 uc at this spot? (14c = 10 6c) give your answer in sl unit rounded to two decimal places.

-2370000 N force acts on the charge particle    

Explanation:

We have given electric field E = 790000 N/C

Charge

We know that force on any charge particle due to electric field is given by

, here q ia charge and E is electric field

So force

So -2370000 N force acts on the charge particle  

the answer is a 3.8cm

explanation:

i believe the answer would be:

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