Physics, 14.09.2019 10:20 edwin3448

Newton's second law: rudolph the red nosed reindeer is pulling a 25 kg sled across the snow in a field. the coefficient of kinetic friction is .12 the rope that is pulling the sled is coming off at a 29 degree angle above the horizontal. find the force in the rope when the acceleration is .12 m/s^2.

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Answer from: nika0001

F=39,68N

Explanation:

Data:

Mass m=25 Kg

Coefficient of kinetic friction $\mu=0.12$

Angle = $29^{0}$

Acceleration = $0.12 \frac{m}{s^{2} }$

Solution:

By Newton's first law we know that for the x-axis:

$F_{rope_x}-F_f=F_R$ Where F_R is the resulting force, and F_f is the friction force.

And for the y-axis:

$F_{rope_y}+N=W$ , where N is the normal force, and W is the weight of the sled.

We know that the resulting force's acceleration is $0.12 \frac{m}{s^{2} }$ , and by using Newton's second law, we obtain:

F=m.a

$F_R=25Kg. 0.12\frac{m}{s^2} \\ F_R=3N$ .

Now, the horizontal component of the force in the rope will be given by

$F_{rope_x}=F_{rope}.cos(29^0)=F_R+F_f$ , since the resulting force is completely on the x-axis, and the friction opposes to the speed of the sled.

To obtain the friction force, we must know the normal force:

$F_f=\mu. N$

Clearing N in the y-axis equation:

$N=W-F_{rope_y}=W-F_{rope}.sin(29^0)$

So we can express the x-axis equation as follows:

$F.cos(29^0)=F_R+\mu.(W-F_{rope}.sin(29^0))$

Finally, solving for F we get

$F = (F_R + \mu. m.g) / (cos (29^0) + \mu.sin (29^0))$

F=39,68N

Answer from: Quest

the rearrangement of particles in a physical change. hope this

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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Newton's second law: rudolph the red nosed reindeer is pulling a 25 kg sled across the snow in a fi...

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