Amass attached to a horizontal spring is stretched by 10 cm and released. it takes 0.2 sec for the mass to reach the equilibrium position. the mass is then stretched to 30 cm and released. how long does it take the mass to reach the equilibrium position?

No change

Explanation:

The time period of an oscillating body depends on the mass of the body attached and the spring constant of the spring.

The time taken by the oscillating body to complete one vibration is called the time period of teh body.

As the time period does not depend on the amplitude of the oscillations so the time period does not change as the amplitude changes.

Thus, the time taken by the mass to reach to the equilibrium position remains  same.

b

explanation:

bc its just b