Acheetah is walking at 5.0m/s when it sees a zebra 35m away. what acceleration would be required for the cheetah to reach 25.0 m/s in that distance?

Acceleration,

Explanation:

Given that,

Initial speed of the Cheetah, u = 5 m/s

Distance covered, s = 35 m

Final speed of the cheetah, v = 25 m/s

We need to find the acceleration required for the cheetah to reach its final speed. The formula is as follows :

So, the acceleration of the cheetah is . Hence, this is the required solution.

scorpions are,

c.arachnids

  scorpions are animals in the order scorpiones, under the class arachnida, which makes them a distant cousin of spiders

happy to

pls mark as brainliest.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow