Calculate the the wavelength of the first balmer series of hydrogen is 6562 following: a) the ionization potential, and b) the first excitation potential of the hydrogen atom.

(a) 13.6 eV

(b) 10.2 V

Explanation:

a) Ionization potential energy is defined as the minimum energy required to excite a neutral atom to its ionized state i.e basically  the minimum energy required to excite an electron from n=1 to infinity.

Energy of a level, n, in Hydrogen atom is,

Now ionization potential can be calculated as

Substitute all the value of energy and n in above equation.

Therefore, the ionization potential is 13.6 eV.

b) This is the energy required to excite a atom from ground state to its excited state. When electrons jumps from ground state level(n=1) to 1st excited state(n=2) the corresponding energy is called 1st excitation potential energy and corresponding potential is called 1st excitation potential.

So, 1st excitation energy = E(n 2)- E(n = 1)

Now we can find that 1st excitation energy is 10.2 eV which gives,

Therefore, the 1st excitation potential is 10.2V.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

current flows in a wire