An electric field of 710,000 n/c points due west at a certain spot. what is the magnitude of the force that acts on a charge of -6.00 c at this spot? (14c - 10 6c) give your answer in si unit rounded to two decimal places

The magnitude of force is

Solution:

As per the question:

The strength of Electric field due west at a certain point,

Charge, Q = - 6 C

Now, the force acting on the charge Q in the electric field is given by:

Here, the negative sign indicates that the force acting is opposite in direction.

the answer is d. 4

hope this

also the more points you give the faster your questions get answered

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.