What is the energy stored between 2 carbon nuclei that are 1.00 nm apart from each other? hint: carbon nuclei have 6 protons and 1.00 nm = 1.00x10^-9m
a. 8.29x10^-18j
b. 2.30x10^-19j
c. 8.29x10^-10j
d. 8.29x10^-9j
e. 0 j

Explanation:

Given that:

p = magnitude of charge on a proton =

k = Boltzmann constant =

r = distance between the two carbon nuclei = 1.00 nm =

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

So, the potential energy between the two nuclei of carbon is as below:

Hence, the energy stored between two nuclei of carbon is .

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer