The specific heat capacity of ice is about 0.5 cal per gram per degree celsius. suppose it remains at that value all the way to absolute zero. determine the quantity of heat needed to change a 1 g ice cube at absolute zero to 1 g of boiling water. hint: you will need to do this problem in three parts (a) heat needed to change temperature from absolute zero to melting temperature of water, (b) heat needed to melt the ice, (c) heat needed to change temperature from melting temperature to boiling temperature. the final answer is determined by adding the results from parts (a), (b), and (c).

316.5 cals.

Explanation:

(a) heat needed to change temperature from absolute zero to melting temperature of ice

= mass x specific heat x rise in temperature

= 1 x .5 x 273 = 136.5 cals

b ) heat needed to melt the ice

= mass x latent heat of melting

= 1 x 80 = 80 cals

c ) heat needed to change temperature from melting temperature to boiling temperature.

mass x specific heat x rise in temperature

1 x 1 x 100

= 100 cals

Total heat required

= 136.5 + 80 + 100

= 316.5 cals.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

ice to water 1 water to vapour 2 latent heat