Awheel initially spinning at wo = 50.0 rad/s comes to a halt in 20.0 seconds. determine the constant angular acceleration and the number of revolutions it makes before stopping. an athlete is holding a 2.5 meter pole by one end. the pole makes an angle of 60 with the horizontal. the mass of the pole is 4 kg. determine the torque exerted by the pole on the athlete's hand. (the mass of the pole can be assumed to be concentrated at the center of mass.)

(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

Explanation:

Given that,

Initial spinning = 50.0 rad/s

Time = 20.0

Distance = 2.5 m

Mass of pole = 4 kg

Angle = 60°

We need to calculate the angular acceleration

Using formula of angular velocity

The angular acceleration is -2.5 rad/s²

We need to calculate the number of revolution

Using angular equation of motion

Put the value into the formula

The number of revolution is 500 rad.

(II). We need to calculate the torque

Using formula of torque

Put the value into the formula

Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.

(II). The torque is 84.87 N-m.

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )