The electric field 14.0 cm from the surface of a copper ball of radius 2.0 cm is directed toward the ball's center and has magnitude 9.0 ✕ 10^2 n/c. how much charge is on the surface of the ball (in c)? (include the sign of the value in your answer.)

Q = - 256 X 10⁻⁷ C .

Explanation:

Electric field due to a charge Q at a distance d from the center is given by the expression

E = k Q /d² Where k is a constant and it is equal to 9 x 10⁹

Put the given value in the equation

9 x 10² =

Q =

Q = - 256 X 10⁻⁷ C .

It will be negative in nature as the field is directed towards the center.

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