Aball is thrown vertically upward with a speed of 20 m/s. when will it reach the maximum height? what is the maximum height reached?

2.04 sec and  20.38 meters

Explanation:

upward speed of the ball u = 20 m/s

final velocity of the ball v= 0 m/s

we know that

on solving we get

h= 20.38 meters. this the maximum height it will reach.

to calculate when it will reach maximum height

use u= gt

t= u/g

⇒ t= 20/9.81 = 2.04 sec after this much time it will reach to its maximum height.

Time taken by the ball to reach maximum height = 2.041 seconds.

Maximum height that ball reached = 20.41 meters.

Explanation:

Given that the initial speed of the ball,

We know, when the ball moves in upward direction, the acceleration due to gravity acts on it in downwards direction, therefore the affecting acceleration that acts on the ball .

g is the acceleration due to gravity having value .

Also, the final speed of the ball at its maximum height will be 0, i.e.,

To find the time taken by ball to reach maximum height.

Let it reaches the maximum height in time t, using the following relation of Kinematics,

To find the maximum height.

Let the maximum height upto ball goes be s, then using,

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up

c. magnitude and direction