Ahot air balloon has just lifted off and is rising at the constant rate of 1.20 m/s. suddenly, one of the passengers realizes she has left her camera on the ground. a friend picks it up and tosses it straight upward with an initial speed of 10.5 m/s. if the passenger is 3.00 m above her friend when the camera is tossed, how much time does it take for the camera to reach her?

Explanation:

Speed of balloon, u = 1.2 m/s

Initial distance between balloon and camera, d = 3 m

initial speed of camera, u' = 10.5 m/s

Let the camera reaches the balloon in time t.

The distance traveled by the balloon in time t = velocity of balloon x t = 1.2 t

So, the distance traveled by the camera in time t = 3 + 1.2 t ..... (1)

By using the second equation of motion

here, s s the distance traveled  by the camera, u' be the initial speed of the camera, a be the acceleration due to gravity. By substituting the values, we get

t = 0.4 s or 1.49 second

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force