Amodel rocket climbs 200 m in 4 seconds. if was moving 10 m/s to begin with, what is it’s final velocity?

So first Identify all the given Varibales so u can choose which Eqauton to use

D=200m
T=4s
Vi=10m/s
Vf=?

You should this equation

D= 0.50(Vf+Vi)T

Plug in the values

200= 0.50 (Vf+10) 4

Divide the 4 out of the right side and if you do sumthing to one side you gotta do it to the other

200 divided by 4= 0.50(Vf+10)
50= 0.50(Vf+10)

Now expand the 0.50

So 50= 0.5Vf + 5 (because 0.5 times 10 is 5)

Now get rid of the 5

50-5= 0.5Vf

45 =0.5Vf now Divide the 0.5 out

45 divided by 0.5 = Vf

And 45/0.5 is 90

So 90=Vf

Therefore the final Velocity is 90m/s

Yes

Because the dept in the ocean