During a baseball game, a batter hits a high
pop-up.
if the ball remains in the air for 5.47 s, how
high does it rise? the acceleration of gravity
is 9.8 m/s.
answer in units of m.

The maximum height of the ball is 36.65 m.

Explanation:

Given that,

Time = 5.47 sec

The ball must be at top point in half of total time.

We need to calculate the height

Using equation of motion

Where, s = height

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

Hence, The maximum height of the ball is 36.65 m.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

the answer is 12 as i may remember

: )