An acrobat mass 55 kg is going by her teeth from a metal steel wire that has an unstretched length of 1.5 meter and diameter 1.66 mm. determine the stretch of steel wire.

It's have to be 12 or idk

Sorry i don’t know what to do

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.