Atest of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m. find the acceleration, assuming it to be constant as a fraction of the free-fall acceleration. the acceleration due to gravity is 9.81 m/s 2 . answer in units of g

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

Converting to m/s²

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

Hence, acceleration of the car is -0.64525g

answer: i don't know the answer good luck

explanation:

b would be the answer