Apomegranate is thrown from ground level straight up into the air at time t=0 with velocity 240 feet per second. its height in feet at t seconds is f(t)=-16 t^2+240 t. find the time it hits the ground and the time it reaches its highest point. hits the ground when t= 4 second (include units) reaches highest point when t= 2 second (include units) maximum height =

a)

b)

c)

Explanation:

From the exercise we have the equation of height and the initial velocity of the pomegranate

a)To find the time that it hits the ground we know that its position is 0

Solving for t using quadratic equation

or

Since time can not be 0, the answer is t=15s

b) To find the time that it reaches its highest point we need to analyze the velocity at that time

At the highest point its velocity is 0

c) To find the maximum height we need to use f(t) with t=7.5