Aball is thrown straight up into the air with an initial velocity of 50 ft/sec. the height h(t) of the ball after t seconds is given by latex: h\left(t\right)=50y-16t^2h ( t ) = 50 y − 16 t 2. what is the average velocity for the time period beginning when t=1 and lasting 0.1 seconds?

The average velocity for the time period beginning when t=1 and lasting 0.1 seconds = 16.40 ft/s.

Explanation:

Given that the height of the ball at time t is

The average velocity of an object is defined as the total displacement covered by the particle divided by the total time taken in covering that displacement.

If are the heights of the ball at time and , then the total displacement covered by the ball from time to is .

Thus, the average velocity of the ball for the time interval  is given by

For the time interval, beginning when t = 1 second and lasting 0.1 seconds,

come closer and become far apart and become steam/gas