Astone is thrown straight up from the ground with an initial speed of 44 m/s. at the same instant, a stone is dropped from a height of hmeters above ground level. the two stones strike the ground simultaneously. find the heighth. the acceleration of gravity is 9.8 m/s2.answer in units of m.

394.26 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

Total time taken by the stone to reach the ground is 4.49+4.49 = 8.97 seconds

The times are equal so,

The height is 394.26 m

the answer is 3.1 his answer is wrong mines is right

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm