Astreet light is on top of a 15 foot pole. a person who is 6 feet tall walks away from the pole at a rate of 4 feet per second. at what speed is the length of the person’s shadow growing? 1. speed = 23 9 ft/sec mcguire (am89323) – 2.6 related rates – toshner – (ab-4) 4 2. speed = 3 ft/sec 3. speed = 25 9 ft/sec 4. speed = 8 3 ft/sec 5. speed = 26 9 ft/sec

(4). 8/3 ft/sec.

Speed of person's shadow growing = 2.66 ft/sec.

In the question,

The height of the pole is = 15 foot

Height of the person = 6 foot

Rate of walking away from the pole, v = dy/dt = 4 ft/sec.

Now,

Let us say the length of shadow is = x

and,

Distance of person from the pole is = y

So,

In the triangle EDC and EAB, from the similar triangle properties, we can say,

Now,

On differentiating the equation w.r.t, time, t, we get,

Therefore, the Speed at which the person's shadow is growing is 2.66 ft/sec.

Hence, the correct option is (4).

the answer for apex is the lowest

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.