Honeybees acquire a charge while flying due to friction with the air. a 100 mg bee with a charge of +23 pc experiences an electric force in the earth’s electric field, which is typically 100 n/c, directed downward.
a) what is the ratio of the electric force on the bee to the bee's weight?
b) what electric field strength would allow the bee to hang suspended in the air? express your answer with the appropriate units.

(A) ratio of electric force to weight will be  

(b) Electric field will be

Explanation:

We have given mass of bee = 100 mg  =

Charge on bee

Electric field E = 100 N/C

Weight of the bee

Electric force on the bee

So the ratio of electric force on the bee and weight is

(B) To hold the bee in air electric force must be equal to weight of bee

So

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

we need to know the time interval during which the force acts. impulse of force = momentum change