Arugby player runs with the ball directly toward his opponent's goal, along the positive direction of an x axis. he can legally pass the ball to a teammate as long as the ball's velocity relative to the field does not have a positive x component. suppose the player runs at speed 3.5 m/s relative to the field while he passes the ball with velocity v with arrowbp relative to himself. if v with arrowbp has magnitude 5.6 m/s, what is the smallest angle it can have for the pass to be legal?

minimum angle is 128.69°

Explanation:

given data

player velocity with respect ground v1 = 3.5 m/s

ball velocity with respect himself v2 = 5.6 m/s

to find out

smallest angle

solution

we know ball velocity with respect field will be

ball velocity = v1  +v2

ball velocity = 3.5 + 5.6 = 9.1m/s

we consider angle that player hit ball is θ

then by as per figure triangle

cosθ =

cosθ =

θ = 51.31

so minimum angle is 180 - 51.31 = 128.69°

the independent variable, or the one that is intentionally manipulated is the speed.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s