The radii of curvature of a biconvex lens are 4 cm and 15 cm. the lens is in air, its index of refraction is 1.5. an object is at 1 m before the front surface of the lens. calculate the distance of the image from the back surface of the lens.

v = 6.315 cm

Explanation:

given,

R₁ = 4 cm = 0.04 m

R₂ = 15 cm = 0.15 m

n =1.5

v = 0.06315 m

v = 6.315 cm  

hence, the distance of the image from the back surface is v = 6.315 cm

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )

increase masses, decrease separation