Atrough is 3 meters long, 2 meters wide, and 4 meters deep. the vertical cross-section of the trough parallel to an end is shaped like an isoceles triangle (with height 4 meters, and base, on top, of length 2 meters). the trough is full of water (density 1000 kg m 3 1000kgm3 ). find the amount of work in joules required to empty the trough by pumping the water over the top. (note: use g = 9.8 m s 2 g=9.8ms2 as the acceleration due to gravity.)

work done is 470400 J

Explanation:

given data

long = 3 m

wide = 2 m

deep = 4 m

density = 1000 kg/m³

to find out

Find the amount of work in joules

solution

we know here volume = area ×  length

so

area = 0.5 ×base×height

area = 0.5 ×2×4

area = 4 m²

so volume = 4 × 3 = 12 m³

and

weight of water = volume ×density×g

weight = 12 × 1000 × 9.8

weight = 117600 N

so

work done = weight × height

work done = 117600× 4

work done = 470400 J

this could be newton#'s law of cooling. the cooling curve is exponential

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.