Kinematics in one dimension problem:
cars a and b are racing each other along the same straight road in the following manner: car a has a head start and is a distance da beyond the starting line at t=0. the starting line is at x=0. car a travels at a constant speed va. car b starts at the starting line but has a better engine than car a, and thus car b travels at a constant speed vb, which is greater than va.
how long after car b started the race will car b catch up with car a?
express the time in terms of given quantities.

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

answer: option c.

explanation: