Afirefighting crew uses a water cannon that shoots water at 30.0 m/s at a fixed angle of 45.0 ∘ above the horizontal. the firefighters want to direct the water at a blaze that is 10.0 m above ground level. how far from the building should they position their cannon? there are two possibilities (d1

The distance from the building is 11.41 m.

Explanation:

Given that,

Speed = 30.0 m/s

Angle = 45.0°

Distance = 10.0 m

We need to calculate the vertical component

Using formula of vertical component

We need to calculate the time

Using equation of motion

Put the value into the formula

On neglecting of higher value of t

Then use the horizontal component

We need to calculate the distance

Put the value into the formula

Hence, The distance from the building is 11.41 m.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s