If the current through a resistor is cut in half, how does the power dissipated by the resistor change? (p=0vi=1^ 2 r= v^ 2 r )

1/4

Explanation:

P = IV, and V = IR, so P = I²R.

If R is held constant, and I is cut in half, then power becomes:

P = (I/2)²R

P = 1/4 I²R

So the power reduces by a factor of 4.

answer; ///i believe that the correct answer is (carbon); good luck

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2