1) Joule
2) kgm²/s²
3) 10%
Explanation:
Question 1)
Luminosity is defined as the total amount of energy released from an object in a unit amount of time.
This means Luminosity is the ratio of energy and time.
Unit of Energy is Joules and Unit of Time is seconds, so unit of Luminosity would be Joule per second or Watts.
So, from the given options, the unit which would be used in Luminosity calculations is Joule.
Question 2)
Work = Force x Distance
SI unit of Work is Joule
SI unit of Force is Newton or kgm/s²
SI unit of Distance is meter(m)
Unit of Work = Unit of Force x Unit of Distance
Joule = kgm/s² x m
Joule = kgm²/s²
This means, the correct description of joule in terms of SI base units is kgm²/s²
Question 3)
Value of gravitational constant from the experiment = Nm²/kg²
The accepted or actual value of the gravitational constant = Nm²/kg²
We need to calculate the percentage error. Percentage error is defined as:
Here, original value is the accepted value. Using the values in this formula, we get:
Thus, this means the percentage error in the calculation of gravitational constant was 10%.