Asteel ball with mass m=5.21 g is moving horizontally with speed =412 m/s when it strikes a block of hardened steel with mass =14.8 kg (initially at rest). the ball bounces off the block in a perfectly elastic collision. (a) what is the speed of the block immediately after the collision? m/s ( ± 0.002 m/s) (b) what is the impulse exerted on the block?

a) The speed of the block immediately after the collision is .

b) The impulse exerted on the block is .

Explanation:

Hi

a) As this is a perfectly elastic collision, we can use the formula  , due , we obtain . Then with the data that we know and , therefore or adding uncertainty.

b) Now that we know the speed we can use

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

no sign of dia of fuel cell