Object a is moving due east, while object b is moving due north. they collide and stick together in a completely inelastic collision. momentum is conserved. object a has a mass of ma = 18.5 kg and an initial velocity of v0a = 8.15 m/s, due east. object b, however, has a mass of mb = 30.5 kg and an initial velocity of v0b = 5.00 m/s, due north. find the magnitude of the final velocity of the two-object system after the collision.

v =4.36 m/s

Explanation:

given,

mass of object A = 18.5 Kg

initial velocity of object A = 8.15 m/s in east

mass of object B = 30.5 kg

initial velocity of object B = 5 m/s

P = 214. 45 N s

velocity after collision is equal to

v =4.36 m/s

hence, velocity after collision is equal to 4.36 m/s

The magnitude of the final velocity of the two-object system is

Explanation:

As the Momentum is conserved, we can compare the instant before the collision, and the instant after. Also, we have to take in account the two components of the problem (x-direction and y-direction).

To do that, we put our 0 of coordinates where the collision takes place.

So, for the initial momentum we have that

Now, this is equal to the final momentum (in each coordinate)

So, we equalize each coordinate and get each final velocity

Finally, to calculate the magnitude of the final velocity, we need to calculate

which, replacing with the previous results, is

Therefore, the outcome is

8 meters above the spring