An object starts from rest at the origin (x0 = 0) and travels in a straight line with a constant acceleration (a = constant). suppose the relation between the position (x) and time (t) is given by x = (3.4 m/s2) t2 what is the acceleration of the object?

Explanation:

Given that,

An object starts from rest at the origin (x₀ = 0) and travels in a straight line with a constant acceleration (a = constant).

The relation between the position (x) and time (t) is given by :

Let v is the velocity of the object.

Let a is the acceleration of the object. It is given by :

So, the acceleration of the object is . Hence, this is the required solution.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow