Suppose a nascar race car rounds one end of the martinsville speedway. this end of the track is a turn with a radius of approximately 57.0 m . if the track is completely flat and the race car is traveling at a constant 27.5 m/s (about 62 mph ) around the turn, what is the race car's centripetal (radial) acceleration?
what is the force responsible for the centripetal acceleration in this case?
friction, normal, gravity, or weight?

Friction Force

Explanation:

As we know that centripetal force is the product of mass and centripetal acceleration

so we know that

so here we have

so we have

This acceleration is given by the force which may be towards the center of the circular path

Here in the above case it is possible due to friction force.

the temperature and the pressure affect solubility. temperature affects by changing the properties of the solvent. the increase in pressure increases solubility, the decrease in pressure decreases solubility.

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.