What is the repulsive force between two pith balls that are 9.00 cm apart and have equal charges of -28.0 nc?

Force,

Explanation:

Given that,

Charges on pith balls,

Distance between balls, d = 9 cm = 0.09 m

Let F is the repulsive force between two pith balls. We know that the repulsive force between two charges is given by :

F = 0.000871 N

or

So, the repulsive force between the pith balls is . Hence, this is the required solution.

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