Your favorite professor decided to throw in the air a marker above his head (vertically). if the marker leaves his hand at a height of 1.2 m from the ground with an initial velocity of 20 m/s, when would the marker reach the highest point in the air (1.6 m from the ground)?

Explanation:

From the exercise we know

To find how long does it takes the marker to reach the highest point we need to use the equation of position:

Now, we need to use the quadratic formula:

Solving for t

or

So, the answer is t=4.06s because the other option is almost 0 and doesn't make any sense for the motion of the marker

temp rises, and expansion

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach