Atangential force of 1500 n exerted upon the upper surface of a cube of 20 cm edge. calulate the shear modulus of the cube matarial if the result displacement was 0.1cm

The shear modulus of the cube material is  .

Explanation:

Given that shearing force applied F = 1500 N  

Displacement produced x = 0.1 cm=0.001 m  

side of the cube =20 cm = 0.2 m

Since the object is a cube the upper surface is  a square and it is on this surface the shearing  

force is applied

area of the upper surface

shear strain = tan⁡ θ =  

shearing stress =

modulus of rigidity η

its a 5.5 n

glad that