Your town is installing a fountain in the main square. if the water is to rise 28.0 m (91.8 feet) above the fountain, how much pressure must the water have as it moves slowly toward the nozzle that sprays it up into the air? assume atmospheric pressure equal to 100,000. pa and g=9.81 m/s2.

Explanation:

Given that,

The water is to rise to a height of 28 meters. Let P is pressure must the water have as it moves slowly toward the nozzle that sprays it up into the air.

We know that, the atmospheric pressure is :  

P can be calculated as :

P = 374680 Pa    

So, the pressure of 374680 Pascal must the water have as it moves slowly toward the nozzle that sprays it up into the air. Hence, this is the required solution.              

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.

answer( sicar );