Asailboat has a mass of 1.20 ✕ 103 kg and is acted on by a force of 2.90 ✕ 103 n toward the east, while the wind acts behind the sails with a force of 3.90 ✕ 103 n in a direction 45° north of east. find the magnitude (in m/s2) and direction (in degrees north of east) of the resulting acceleration.

a = 4.04 m/s2

north of east

Explanation:

The mass of the boat is m = 1200 kg

The forces acting  due to wind on the boat is Fwind = 3900 N j^ (north)

and The forces acting due to water  on the boat is Fwater = 2900 N i^ (east)

The net force on the boat is F = 2900 N i^ + 3900 N j^

The horizontal component of the net acceleration is ax = Fwater/m = 2.41 m/s2

vertical component of the net acceleration is ay = Fwind/m = 3.25 m/s2

Net acceleration is

a = 4.04 m/s2

The direction of the net acceleration is =

=north of east

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force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2