Along straight wire has fixed negative charge with a linear charge density of magnitude 4.6 nc/m. the wire is to be enclosed by a coaxial, thin-walled, nonconducting cylindrical shell of radius 2.2 cm. the shell is to have positive charge on its outside surface with a surface charge density σ that makes the net external electric field is zero. calculate σ.

-33.3 * 10^9 C/m^2( nC/m^2)

Explanation: In order to solve this problem we have to use the gaussian law, the we have:

Eoutside =0 so teh Q inside==

the Q inside= 4.6 nC/m*L + σ *2*π*b*L where L is the large of the Gaussian surface and b the radius of the shell.

Then we simplify and get

σ= -4.6/(2*π*b)= -33.3 nC/m^2

answer: i pick a

explanation:

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this