Two forces and are applied to an object whose mass is 9.31 kg. the larger force is . when both forces point due east, the object's acceleration has a magnitude of 0.626 m/s2. however, when points due east and points due west, the acceleration is 0.340 m/s2, due east. find (a) the magnitude of and (b) the magnitude of . (a) number entry field with correct answer 4.5 units entry field with correct answer

the magnitudes of the two forces are 45.N and 1.5 N

Explanation:

This in a problem of composition of forces, as the forces are on a single axis, East-West, we can work as a problem of a single dimension, write Newton's second law for each case n

   • Two forces to the east

        F1 + F2 = m a1

  • One force to the east and the other to the west

        F1 - F2 = m a2

We see that we have a system of two equations with two unknowns, we proceed to solve it

We add sides equations

        F1 + F2 = m a1

        F1 - F2 = m a2

       2F1 = m (a1 + a2)

       F1 = m (a1 + a2) / 2

       F1 = 9.31 (0.626 +0.340) / 2

       F1 = 4.5 N

We substitute in one of the two equations and find the other force

       F1 + F2 = m a1

       F2 = m a1 - F1

       F2 = 9.31 0.646 - 4.5

       F2 = 1.5 N

     These are the magnitudes of the two forces 45.N and 1.5 N

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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