An object, initially at rest, is subject to an acceleration of 34 m/s2. how long will it take for that
object to travel 3400 m?

14 s

Explanation:

Given:

v₀ = 0 m/s

a = 34 m/s²

Δx = 3400 m

Find: t

Δx = v₀ t + ½ at²

(3400 m) = (0 m/s) t + ½ (34 m/s²) t²

t = 14.1 s

Rounded to two significant figures, it takes 14 seconds.

15.3 cos 65 degrees trig

the answer is b, have negligible mass