Aball is dropped. what is its velocity after 3 seconds? the acceleration due to gravity is 10 m/s^2

part 2 - what would the balls velocity be three seconds after it was dropped on the moon, where the acceleeration due to gravity is 1.6 m/s

Part 1 - 30 m/s

Part 2 - 5 m/s

Explanation:

For these kinds of questions, write out what you're given and what you're trying to find. Usually there's an equation that puts them all together, allowing you to solve for the unknown (it's helpful to understand how the equations are made in the first place but even if you choose not to you should memorize them).

Part 1

Given:

vi = 0

a = 10

t = 3

vf = ?

The equation relating these variables is the basic one for acceleration:

a = (vf - vi) / t

10 = (vf - 0) / 3

vf = 30

Part 2

Given: (everything is the same as part 1, except a is now 1/6 of what it was)

vi = 0

a = 10/6

t = 3

vf = ?

a = (vf - vi) / t

10/6 = (vf - 0) / 3

vf = 5

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