Aparticle initially located at the origin has an acceleration of a 2.00j m/s2 and an initial velocity of v-6.00i m/s. (a) find the vector position of the particle at any time t (where t is measured in seconds). ti+ t2 j) m (b) find the velocity of the particle at any time t. i + tj) m/s (c) find the coordinates of the particle at t 5.00 s. (d) find the speed of the particle at t 5.00 s. m/s

Explanation:

The initial position of the particle, , is:

the initial velocity is:

and the initial acceleration:

The position at time t is

So, for our problem is:

The velocity at time t is

So, for our problem is:

At time 5.00 seconds the position will be:

and the speed will be :

ι вєℓιєνє ιт ιѕ тнє fιяѕт ¢нσι¢є(α.)

нє ѕнσυℓ∂ ѕмιℓє ρσℓιтℓу αи∂ ѕρєαк тσ тнє ρєяѕσи ωнσ ιѕ ιитєяяυριиg αfтєя тнє ∂ιѕ¢υѕѕισи

нσρє ι ¢συℓ∂ нєℓρ.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j