Difficult to tackle a heavier player travelling at the same speed?
because their body mass.
is
mere
the stick. in terms of kinetic energy and work
b) a hockey player traps a fast ball with deft use of the stick. in terms of ki
done, why is it more difficult to stop a faster ball that is otherwise identical
because the veloci
c) a car of mass 800 kg is travelling at 30 m/s (almost im
elling at 30 m/s (almost 70 mph). the car then brakes suddenly
and stops with a braking distance of 75 m. find:
i) the initial kinetic energy of the car 360oo gu bolo 360o
ii) the final kinetic energy of the car 300oooj
iii) the change in kinetic energy of the car 330,00oj
iv) the work done on the car by the brakes
v) the braking force on the car.

your answer would be fusion

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.