Acertain elevator cab has a total run of 190 m and a maximum speed of 305 m/min, and it accelerates from rest and then back to rest at 1.22 m/s2 . (a) how far does the cab move while accelerating to full speed from rest? (b) how long does it take to make the nonstop 190 m run, starting and ending at rest?

Explanation:

Given

length of run=190 m

maximum speed

time require to reach max speed

v=u+at

distance traveled in t=4.16 s

Now time taken to stop from max speed to zero

v=u+at

t=4.16 s

so the distance travel by car during the deceleration is 10.55 m

total time time taken=4.16+4.16=8.32 s

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