Abullet is fired from a rifle that is held 3.00 m above the ground in a horizontal position. the initial speed of the bullet is 1150 m/s. there is no error in the velocity value. (a) find the time (in s) it takes for the bullet to strike the ground. t = s (b) find the horizontal distance (in m) traveled by the bullet. x = m (c) if the error in time measurements is δt, what will be the equation to calculate error in the horizontal distance (δx)? (assume x is in meters and t is in seconds. do not enter units in your expression. substitute numeric values; the only variable you should enter is δt.) δx =

a) 0.78 s; b) 899.83 m; c) Δx=1150*Δt

Explanation: In order to solve this problem we have to use the kinematic equations for the independent two axis (x-y). The following expressions are:

y=yo+voy-(g*t^2)/2 g is 9.8 the aceletarion of the gravity on the y axis

vfy=voy-g*t

x=xo+vox+(a*t^2)/2   a=o there is not acceleration in the x axis.

vfx=vox+a*t

voy and vox ara the initial velocities for each axis.

yo and xo are the initial positions of teh bullet.

From these equations we can obtain the time

y=0=3-(g*t^2)/2

t^2=3*2/g

t=

t= 0.78 s

To calculate xf= voy*t= 1150 * 0.78= 899.83 m

Finally considering with the last equation we ontain  the error in Δx

in the form:

Δx=1150*Δt  since is linear the dependance with time.

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