Two cars cover the same distance in a straight line. car a covers the distance at a constant velocity. car b starts from rest and maintains a constant acceleration. both cars cover a distance of 460 m in 210 s. assume that they are moving in the +x direction. determine (a) the constant velocity of car a, (b) the final velocity of car b, and (c) the acceleration of car b.

(a) Constant velocity of car A is 2.19 m/sec

(b) Final velocity of car B is 4.62 m/sec

(c) Acceleration of car B is 0.022

Explanation:

We have given that both car travels a distance of 460 m in 210 sec

So distance s = 460 m and time t = 210 sec

(a) AS car A is traveling with constant velocity

So velocity of car A

(c) As car starts from rest its initial velocity u= 0 m/sec

According to second equation of motion

(b) Now from first equation of motion

v=u+at

v=0+0.022×210 = 4.62 m/sec

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